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Proof step 3 from proof bib-ls-same (previous step)

i < 0 ⊦ i < b2i(i2b(i)) ↔ ¬ ~128 ≤ i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i < 0 ∧ ~128 ≤ i % 256 → b2i(i2b(i)) = i % 256
Proof step 5:
¬(i < 0 ∧ ~128 ≤ i % 256), i < 0 ⊦ i < b2i(i2b(i)) ↔ ¬ ~128 ≤ i
Proof step 8:
i < 0 ∧ ~128 ≤ i % 256, i < 0 ⊦ i < i % 256 ↔ ¬ ~128 ≤ i

Rule argument

name: bib-neg-high rotate: F subst: [i] → [i]

Additional information

Used terms: i