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Proof step 23 from proof bib-neg-high (previous step)

j0 < 0, i0 * 256 + j0 < 0, j0 ≤ 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, abs(j0) < 256, i0 < 0 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j0))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 * 256 + j0)).first, j0 < 0 ∧ ~128 ≠ j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs%lsone: ⊦ i < 1 ↔ i ≤ 0; from specification int-abs%nummult-ls: ⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 < (* j) ↔ i0 < (i + j - 1) / i); from specification int-div%sub-ls: ⊦ i - j < i0 ↔ i < j + i0; from specification int-abs%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%mone-05: ⊦ i ≤ ~1 ↔ i < 0; from specification int-abs%nummult-le-01: ⊦ 0 < i ∧ j < 0 → ((* i) * i0 ≤ (* j) ↔ i0 ≤ (j + 1 - i) / i); from specification int-div%sub-le: ⊦ i - j ≤ i0 ↔ i ≤ j + i0; from specification int-abs%minus-add: i < 0 ⊦ (* i) + j = j - ~ i; from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%numlsledel-01: i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j; from specification int-abs%numls-02: ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0; from specification int-abs%neg-13: ⊦ ~ i < j ↔ 0 < j + i; from specification int-abs%abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs%zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult