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Proof step 37 from proof bib-neg-high (previous step)

2 * i0 - 1 < 0, i0 < 0 ⊦ b2i(i2b(bits2int(sgn(bitsinvert(uint2bits(~ i0)) + true ').last ' + false ' + false ' + false ' + false ' + false ' + false ' + false '))) = ~128, i0 = 0, i0 * 256 ≠ ~128 ∧ sgn(bitsinvert(uint2bits(0 - (2 * i0 - 1))) +1).last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: neg-15: ⊦ i + ~ j = i - j; from specification int-abs%minus-02: ⊦ ~(i - 1) = ~ i + 1; from specification int-abs%neg-06: ⊦ 0 - i = ~ i; from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%lsone: ⊦ i < 1 ↔ i ≤ 0; from specification int-abs%nummult-ls: ⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 < (* j) ↔ i0 < (i + j - 1) / i); from specification int-div%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%sub-ls: ⊦ i - j < i0 ↔ i < j + i0; from specification int-abs