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Proof step 51 from proof bib-neg-high (previous step)

i0 * 256 + j0 < 0, j0 ≤ 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, abs(j0) < 256, i0 < 0 ⊦ j0 < 0, b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j0))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 * 256 + j0)).first, j0 < 0 ∧ ~128 ≠ j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: mone-05: ⊦ i ≤ ~1 ↔ i < 0; from specification int-abs%nummult-le-01: ⊦ 0 < i ∧ j < 0 → ((* i) * i0 ≤ (* j) ↔ i0 ≤ (j + 1 - i) / i); from specification int-div%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%zero-ls: ⊦ 0 < i → (i * j < 0 ↔ j < 0); from specification int-mult%ax-04: ⊦ i + 0 = i; from specification int-basic2%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%numlsledel: j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0); from specification int-abs%Abs-pos: ⊦ ¬ j < 0 → abs(j) = j; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult