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Proof step 59 from proof bib-neg-high (previous step)

8 ≠ # fillsgn(8, int2bits(j0)), ~128 < j0, i0 * 256 + j0 < 0, ~128 ≤ j0, i0 * 256 + j0 ≤ ~256, i0 < 0, j0 < 0 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 - 1) + fillsgn(8, int2bits(j0)))))) = j0, ~256 ≠ i0 * 256 + j0 ∧ lastn(8, int2bits(i0 - 1) + fillsgn(8, int2bits(j0))).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult