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Proof step 68 from proof bib-neg-high (previous step)

int2bits(j0) ≠ [], ~256 = i0 * 256 + j0, 8 = # fillsgn(8, int2bits(j0)), j0 < 0, i0 < 0, ~128 ≤ j0, ~128 < j0 ⊦ b2i(i2b(bits2int(int2bits(j0)))) = j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 69:
~256 = i0 * 256 + j0, 8 = # fillsgn(8, int2bits(j0)), j0 < 0, i0 < 0, ~128 ≤ j0, ~128 < j0 ⊦ b2i(i2b(j0)) = j0

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ []; from specification int2bits%int2int-inj: ⊦ bits2int(int2bits(i)) = i; from specification int2bits