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Proof step 17 from proof bib-neg-low (
previous step
)
# int2bits(j) = 8 + 1, # int2bits(j) = 9, j < 0, ~256 < j, j < ~128 ⊦ b2i(i2b(bits2int(int2bits(j).rest))) = 256 + j
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 18
:
# int2bits(j) = 9, j < 0, ~256 < j, j < ~128 ⊦ b2i(i2b(bits2int(int2bits(j).rest))) = 256 + j
Rule argument
Additional information