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Proof step 9 from proof bib-neg-low (previous step)

j < ~128, i0 * 256 + j < ~128, ~256 < j, i0 ≤ 0, j < 0, i0 * 256 + j < 0 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j))))) = j + 256

User applied rule cut formula

And obtained the following new goals

Proof step 10:
256 = 2 ^ 8, j < ~128, i0 * 256 + j < ~128, ~256 < j, i0 ≤ 0, j < 0, i0 * 256 + j < 0 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j))))) = j + 256

Rule argument

fma: 256 = 2 ^ 8

Additional information

Used formulas: 256 = 2 ^ 8