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Proof step 17 from proof bib-on-bits (previous step)

# int2bits(i) ≤ 8 ∧ int2bits(i) ≠ [], ~128 ≤ i, i ≤ 127 ⊦ i = bits2int(lastn(8, mklist(int2bits(i).first, 8 - # int2bits(i)) + int2bits(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ int2bits(j).first ↔ j < 0;