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Proof step 35 from proof bib-on-bits (previous step)

i < 0, ~64 ≤ i, i < ~1 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = bits2int(lastn(8, fillsgn(8, int2bits(i)))), i ∈byte

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 36:
⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127

Rule argument

name: inbyte rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; Used terms: i