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Proof step 38 from proof bib-on-bits (previous step)

i < 64, 0 < i ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = bits2int(lastn(8, fillsgn(8, int2bits(i)))), i ∈byte

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 39:
⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127

Rule argument

name: inbyte rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;%j0 ≠ 0, j < j0 ⊦ i < (* j) → i < (* j0); Used terms: i