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Proof step 14 from proof bib-pos-high (previous step)

i = i0 * 256 + j ∧ 0 ≤ j ∧ j < 256 ∧ 0 < 256 ∧ 0 ≤ i, 0 < j, 127 < j, 127 < i, 0 < i, 64 ≤ i ⊦ j = b2i(i2b(bits2int(lastn(8, int2bits(i))))) + 256, 0 = i, lastn(8, int2bits(i)).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 ≤ j1 ∧ j1 < j → (0 ≤ i0 * j + j1 ↔ 0 ≤ i0);% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;