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Proof step 17 from proof bib-pos-high (previous step)

¬(0 < i0 ∧ 0 ≤ j ∧ j < 256), 0 < i0 * 256 + j, 0 ≤ j, 0 < j, j < 256, 64 ≤ i0 * 256 + j, 127 < i0 * 256 + j, 127 < j, 0 ≤ i0 ⊦ 0 = i0 * 256 + j, j = b2i(i2b(bits2int(lastn(8, int2bits(i0 * 256 + j))))) + 256, lastn(8, int2bits(i0 * 256 + j)).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i + 0 = i;% ⊦ i < j ∧ i = i0 → i0 < j; (forward)%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);% ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (j ≤ i ↔ i = j);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;