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Proof step 39 from proof bib-pos-high (previous step)

8 ≠ # int2bits(j).rest, 9 ≤ # int2bits(j), 0 ≤ i0, 127 < j, 127 < i0 * 256 + j, 64 ≤ i0 * 256 + j, j < 256, 0 < j, 0 ≤ j, 0 < i0 * 256 + j, 0 < i0 ⊦ j = b2i(i2b(bits2int(lastn(8, int2bits(i0) + int2bits(j).rest)))) + 256, 0 = i0 * 256 + j, lastn(8, int2bits(i0) + int2bits(j).rest).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
0 < i0, 0 < i0 * 256 + j, 0 ≤ j, 0 < j, j < 256, 64 ≤ i0 * 256 + j, 127 < i0 * 256 + j, 127 < j, 0 ≤ i0, 9 ≤ # int2bits(j) ⊦ 8 = # int2bits(j).rest, 0 = i0 * 256 + j, j = b2i(i2b(bits2int(lastn(8, int2bits(i0) + int2bits(j).rest)))) + 256, lastn(8, int2bits(i0) + int2bits(j).rest).first

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;