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Proof step 5 from proof bib-pos-high (previous step)

0 < i % 256, 127 < i % 256, 127 < i, 0 < i, 0 ≤ i ⊦ i % 256 = b2i(i2b(i)) + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: num-i2b-pos rotate: F subst: [i] → [i]

Additional information

Used terms: i