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Proof step 62 from proof bib-pos-high (previous step)

~128 ≤ i ∧ i ≤ 127, 0 < i % 256, 127 < i % 256, 0 ≤ i ⊦ i % 256 = i + 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 63:
i < i % 256, 0 ≤ i, 127 < i % 256, i ≤ 127, 0 < i % 256 ⊦ i % 256 = i + 256

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;