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Proof step 14 from proof bib-pos-low (previous step)

i = i0 * 256 + j ∧ 0 ≤ j ∧ j < 256 ∧ 0 < 256 ∧ 0 ≤ i, j ≤ 127, j < i, 127 < i, 0 < i, lastn(8, int2bits(i)).first, 64 ≤ i ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = j, 0 = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ i < i + j ↔ 0 < j;% ⊦ i ≠ j → (i ≤ j ↔ i < j);%j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0);% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;