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Proof step 2 from proof bib-pos-low (previous step)

i % 256 ≤ 127, 0 ≤ i ⊦ b2i(i2b(i)) = i % 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i
Proof step 4:
¬(~128 ≤ i ∧ i ≤ 127), i % 256 ≤ 127, 0 ≤ i ⊦ b2i(i2b(i)) = i % 256
Proof step 28:
~128 ≤ i ∧ i ≤ 127, i % 256 ≤ 127, 0 ≤ i ⊦ i = i % 256

Rule argument

name: num-ibbi rotate: F subst: [i] → [i]

Additional information

Used terms: i