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Proof step 24 from proof bib-pos-low (previous step)

i % 256 ≤ 127, 0 ≤ i, 127 < i, i % 256 < i, 0 < i, 8 ≤ # int2bits(i) ⊦ b2i(i2b(i % 256)) = i % 256, lastn(8, int2bits(i)).first

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [lastn(8, int2bits(i)), boolvar, bits] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: ⊦ lastn(n, bits) = [] ↔ n = 0;%bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: lastn(8, int2bits(i)), boolvar, bits