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Proof step 29 from proof bib-pos-low (previous step)

i ≤ 127, i % 256 ≤ 127, 0 ≤ i ⊦ i = i % 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 30:
⊦ abs(i) < j → i % j = i

Rule argument

seq: ⊦ abs(i) < j → i % j = i subst: [j, i] → [256, i] rotate: F spec: int-div inst: name: mod-zero-05

Additional information

Used simplifier rules: ⊦ 0 ≤ i → abs(i) = i;%j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0); Used terms: 256, i