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Proof step 5 from proof bib-pos-low (previous step)

0 < i, i % 256 < i, 127 < i, 0 ≤ i, i % 256 ≤ 127 ⊦ b2i(i2b(i)) = i % 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
127 < i ⊦ i2b((* i)) = i2b(bits2int(lastn(8, int2bits(i))))
Proof step 7:
127 < i, 0 < i, i % 256 < i, 127 < i, 0 ≤ i, i % 256 ≤ 127 ⊦ b2i(i2b(bits2int(lastn(8, int2bits(i))))) = i % 256

Rule argument

name: num-i2b-pos rotate: F subst: [i] → [i]

Additional information

Used terms: i