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Proof step 19 from proof bint-and-011x-bits2unit (previous step)

~2147483648 ≤ i, i < 0 ⊦ fillsgn(32, int2bits(i)) = [], bits2int(fillsgn(32, int2bits(i))) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ bits ≠ [] → bits2int(fillsgn(n, bits)) = bits2int(bits)

Rule argument

seq: ⊦ bits ≠ [] → bits2int(fillsgn(n, bits)) = bits2int(bits) subst: [bits, n] → [int2bits(i), 32] rotate: F spec: int2bits inst: name: bits2int-fill

Additional information

Used simplifier rules: ⊦ bits2int(int2bits(i)) = i;% ⊦ int2bits(j) ≠ []; Used terms: int2bits(i), 32