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Proof step 8 from proof bint-band-011x-neg (previous step)

i < 0 ∧ ¬ false ∈ int2bits(2 ^ 32 - 1).rest ∧ 0 ≤ 2 ^ 32 - 1, ~2147483648 ≤ i, i < 0 ⊦ (i + 1) % ((2 ^ 32 - 1) + 1) + (2 ^ 32 - 1) = i + 4294967296

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
~2147483648 ≤ i, i < 0 ⊦ (i + 1) % 4294967296 = 1 + i

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ false ∈ int2bits(4294967295).rest;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + (* j) = i0 + (* j0) ↔ i = i0 + (j0 - j);