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Proof step 2 from proof bint-fillsgn-len (previous step)

~2147483648 ≤ i, i ≤ 2147483647 ⊦ # fillsgn(32, int2bits(i)) = 32

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bits ≤ n → # fillsgn(n, bits) = n
Proof step 4:
¬ # int2bits(i) ≤ 32, ~2147483648 ≤ i, i ≤ 2147483647 ⊦ # fillsgn(32, int2bits(i)) = 32

Rule argument

seq: ⊦ # bits ≤ n → # fillsgn(n, bits) = n subst: [bits, n] → [int2bits(i), 32] rotate: F spec: bitopsaux inst: name: fill-length

Additional information

Used terms: int2bits(i), 32