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Proof step 1 from proof bint-is-cast (conclusion)

⊦ bi2i(i2bi(i)) = cast(32, i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ i ∈bint → i2bi(i) = i2bi(bits2int(lastn(32, int2bits(i))))
Proof step 3:
¬ ¬ i ∈bint ⊦ bi2i(i2bi(i)) = cast(32, i)
Proof step 6:
¬ i ∈bint ⊦ bi2i(i2bi(bits2int(lastn(32, int2bits(i))))) = cast(32, i)

Rule argument

name: int2bint-out rotate: F subst: [i] → [i]

Additional information

Used terms: i