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Proof step 24 from proof bint-is-cast (previous step)

32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), ~2147483648 ≤ cast(32, i) ∧ cast(32, i) ≤ 2147483647, i ∈bint

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
32 < # int2bits(i) ⊦ bi2i(i2bi(cast(32, i))) = cast(32, i), i ∈bint, ¬ cast(32, i) < ~2147483648 ∧ ¬ 2147483647 < cast(32, i)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;