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Proof step 2 from proof bint-mod (previous step)

j ∈bint ⊦ j = 0, (i % j)∈bint

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i ∈bint ↔ ~2147483648 ≤ i ∧ i ≤ 2147483647
Proof step 4:
j ∈bint ⊦ j = 0, ~2147483648 ≤ i % j ∧ i % j ≤ 2147483647

Rule argument

spec: inst: name: inbint seq: ⊦ i ∈bint ↔ ~2147483648 ≤ i ∧ i ≤ 2147483647 subst: [i] → [i % j] flags: rewrite, current

Additional information

Used terms: i % j