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Proof step 2 from proof bint-num-01 (previous step)

i < ~2147483648 ⊦ ¬ i ∈bint

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inbint: ⊦ i ∈bint ↔ ~2147483648 ≤ i ∧ i ≤ 2147483647;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);