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Proof step 2 from proof bint-num-04 (previous step)

~2147483648 ≤ i, i < 2147483648 ⊦ i ∈bint

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inbint: ⊦ i ∈bint ↔ ~2147483648 ≤ i ∧ i ≤ 2147483647;%i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j;% ⊦ ¬ i ≤ j ↔ j < i;