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Proof step 2 from proof bint-pred (previous step)

~2147483648 ≤ i, i ≤ 2147483647, 0 < i ⊦ i = bi2i(i2bi(i - 1)) + 1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
i = i0 + 1, ~2147483648 ≤ i, i ≤ 2147483647, 0 < i ⊦ i = bi2i(i2bi(i0)) + 1

Rule argument

seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i, 1, i0] rotate: T spec: int-abs inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i, 1, i0