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Proof step 4 from proof bint-succ-notin (previous step)

¬(2 ^ 31 ≤ 1 + i ∧ 1 + i < 2 ^ 32), ~2147483648 ≤ i, i ≤ 2147483647 ⊦ bi2i(i2bi(1 + i)) = ~2147483648, (i + 1)∈bint

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
~2147483648 ≤ i, i < 2147483647 ⊦ bi2i(i2bi(1 + i)) = ~2147483648, i = 2147483647, (i + 1)∈bint

Rule argument

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i ≤ j → (j ≤ i ↔ i = j);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;