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Proof step 3 from proof bint-unsigned (previous step)

0 ≤ i, 0 < i, i < 4294967296, 2147483648 ≤ i ⊦ i2bi(i - 4294967296) = i2bi(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bi2i(bi) = i → (i2bi(i) ≠ bi ↔ false)
Proof step 5:
bi2i(i2bi(i)) ≠ i - 4294967296, 0 ≤ i, 0 < i, i < 4294967296, 2147483648 ≤ i ⊦ i2bi(i - 4294967296) = i2bi(i)

Rule argument

name: bint-equal rotate: F subst: [bi, i] → [i2bi(i), i - 4294967296]

Additional information

Used terms: i2bi(i), i - 4294967296