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Proof step 1 from proof byte-011x-ib (conclusion)

⊦ i2b(band(255, b2i(by))) = by

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ 0 ≤ b2i(by) → band(b2i(by), 255) = b2i(by)

Rule argument

name: byte-011x-pos rotate: F subst: [by] → [by]

Additional information

Used simplifier rules: byte-mod-100x-01: ⊦ (b2i(by) + 1) % 256 = b2i(by) + 1;%byte-add-256: ⊦ i2b(i + 256) = i2b(i);%ibi: ⊦ i2b(b2i(by)) = by;%ibi: ⊦ i2b(b2i(by)) = by;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < 0 → band(i, 255) = (i + 1) % 256 + 255;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ band(i, band(i0, j)) = band(band(i, i0), j);% ⊦ band(i, j) = band(j, i); Used terms: by