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Proof step 5 from proof byte-011x-unsgn (previous step)

b2i(i2b(i)) < 0, 0 ≤ i, i < 256 ⊦ b2i(i2b(i)) + 256 = i

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: num-ibbi rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: bib-upper: ⊦ 127 < i ∧ i < 256 → b2i(i2b(i)) = i - 256;% ⊦ i + (j - i) = j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i = i + j ↔ j = 0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ i < 0 ∧ 0 ≤ j → i ≤ j;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: i