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Proof step 3 from proof byte-127 (previous step)

0 < b2i(by), 126 < b2i(by) ⊦ b2i(by) = 127

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ ¬ 127 < b2i(by)

Rule argument

name: byte-gr-127 subst: [by] → [by]

Additional information

Used simplifier rules: ⊦ ¬ i < j → (i ≠ j ↔ j < i);%i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j; Used terms: by