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Proof step 2 from proof byte-add-256 (previous step)

i + 256 = 1 * 256 + i ⊦ i2b(i + 256) = i2b(i)

User applied rule insert equation

And obtained the following new goals

Proof step 3:
⊦ i2b(1 * 256 + i) = i2b(i)

Rule argument

pos: left 1 flags: discard

Additional information