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Proof step 3 from proof byte-is-cast-01 (previous step)

⊦ b2i(i2b(i)) = b2i(i2b(cast(8, i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ b2i(i2b(i)) = bits2int(lastn(8, fillsgn(8, int2bits(i))))
Proof step 5:
⊦ bits2int(lastn(8, fillsgn(8, int2bits(i)))) = b2i(i2b(cast(8, i)))

Rule argument

name: bib-on-bits rotate: F subst: [i] → [i]

Additional information

Used terms: i