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Proof step 2 from proof byte-law-add-pos (previous step)

0 ≤ i, 0 ≤ j ⊦ i2b(i + j) = i2b(b2i(i2b(i)) + j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i ∧ 127 < i % 256 → b2i(i2b(i)) = i % 256 - 256
Proof step 4:
¬(0 ≤ i ∧ 127 < i % 256), 0 ≤ i, 0 ≤ j ⊦ i2b(i + j) = i2b(b2i(i2b(i)) + j)
Proof step 6:
0 ≤ i ∧ 127 < i % 256, 0 ≤ i, 0 ≤ j ⊦ i2b(i + j) = i2b((i % 256 - 256) + j)

Rule argument

name: bib-pos-high rotate: F subst: [i] → [i]

Additional information

Used terms: i