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Proof step 8 from proof byte-law-add-pos (previous step)

j + i % 256 = i0 + 256, 0 < i % 256, 0 ≤ j, 0 ≤ i, 127 < i % 256 ⊦ i2b(i + j) = i2b(i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information