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Proof step 1 from proof byte-law-and-one (conclusion)

⊦ i2b(band(i, j)) = i2b(band(b2i(i2b(i)), j))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ i2b(band(i, j)) = i2b(band(b2i(i2b(i)), j)), band(i, j) = band(b2i(i2b(i)), j)

Rule argument

Additional information

Used simplifier rules: i2b-noteq: ⊦ i2b(i) ≠ i2b(j) → i ≠ j;