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Proof step 109 from proof byte-law-and-one (previous step)

8 ≠ # fillsgn(8, bitsand(bits, int2bits(i))), 7 = # fillsgn(7, int2bits(i)), int2bits(j) = bits0 + bits, # bits = 8, 0 ≤ i, # int2bits(i) < 8 ⊦ lastn(8, fillsgn(8, bitsand(bits, int2bits(i)))) = lastn(8, fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i))))), bits0 + bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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