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Proof step 129 from proof byte-law-and-one (previous step)

8 = # fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), 8 = # fillsgn(8, bitsand(bits, int2bits(i))), 7 = # fillsgn(7, int2bits(i)), int2bits(j) = bits0 + bits, # bits = 8, 0 ≤ i, # int2bits(i) < 8 ⊦ fillsgn(8, bitsand(bits, int2bits(i))) = fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), bits0 + bits = []

User applied rule cut formula

And obtained the following new goals

Proof step 130:
false ' + fillsgn(7, int2bits(i)) = fillsgn(8, int2bits(i)), 8 = # fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), 8 = # fillsgn(8, bitsand(bits, int2bits(i))), 7 = # fillsgn(7, int2bits(i)), int2bits(j) = bits0 + bits, # bits = 8, 0 ≤ i, # int2bits(i) < 8 ⊦ fillsgn(8, bitsand(bits, int2bits(i))) = fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), bits0 + bits = []
Proof step 139:
8 = # fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), 8 = # fillsgn(8, bitsand(bits, int2bits(i))), 7 = # fillsgn(7, int2bits(i)), int2bits(j) = bits0 + bits, # bits = 8, 0 ≤ i, # int2bits(i) < 8 ⊦ false ' + fillsgn(7, int2bits(i)) = fillsgn(8, int2bits(i)), fillsgn(8, bitsand(bits, int2bits(i))) = fillsgn(8, bitsand(bits, false ' + fillsgn(7, int2bits(i)))), bits0 + bits = []

Rule argument

fma: false ' + fillsgn(7, int2bits(i)) = fillsgn(8, int2bits(i))

Additional information

Used formulas: false ' + fillsgn(7, int2bits(i)) = fillsgn(8, int2bits(i))