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Proof step 142 from proof byte-law-and-one (previous step)

int2bits(j) = bits0 + bits, # bits = 8, 8 = # fillsgn(8, int2bits(i)), i < 0, # int2bits(i) < 8 ⊦ fillsgn(8, int2bits(i)) = [], bits0 + bits = [], lastn(8, fillsgn(8, bitsand(int2bits(i), bits0 + bits))) = lastn(8, fillsgn(8, bits0 + bitsand(bits, fillsgn(8, int2bits(i)))))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ n ≤ # bits → fillsgn(n, bits) = bits subst: [bits, n] → [bits0 + bitsand(bits, fillsgn(8, int2bits(i))), 8] rotate: F spec: bitopsaux inst: name: fillsgn-longer

Additional information

Used terms: bits0 + bitsand(bits, fillsgn(8, int2bits(i))), 8