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Proof step 7 from proof byte-law-and-one (previous step)

⊦ band(i, j) = band(b2i(i2b(i)), j), b2i(i2b(band(i, j))) = b2i(i2b(band(b2i(i2b(i)), j)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ b2i(i2b(i)) = bits2int(lastn(8, fillsgn(8, int2bits(i))))
Proof step 9:
⊦ band(i, j) = band(bits2int(lastn(8, fillsgn(8, int2bits(i)))), j), b2i(i2b(band(i, j))) = b2i(i2b(band(bits2int(lastn(8, fillsgn(8, int2bits(i)))), j)))

Rule argument

name: bib-on-bits rotate: F subst: [i] → [i]

Additional information

Used terms: i