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Proof step 92 from proof byte-law-and-one (previous step)

8 = # fillsgn(8, int2bits(i)), # bits = 8, int2bits(j) = bits0 + bits, # int2bits(i) < 8 ⊦ lastn(8, fillsgn(8, bitsand(int2bits(i), bits0 + bits))) = lastn(8, fillsgn(8, bitsand(bits0 + bits, fillsgn(8, int2bits(i))))), bits0 + bits = [], fillsgn(8, int2bits(i)) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ # bits1 ≤ # bits0 ∧ bits1 ≠ [] ∧ bits1.first → bitsand(bits + bits0, bits1) = bits + bitsand(bits0, bits1) subst: [bits1, bits0, bits] → [fillsgn(8, int2bits(i)), bits, bits0] rotate: F spec: intops inst: name: bitsand-app-true

Additional information

Used terms: fillsgn(8, int2bits(i)), bits, bits0