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Proof step 98 from proof byte-law-and-one (previous step)

8 = # fillsgn(8, int2bits(i)), # bits = 8, int2bits(j) = bits0 + bits, # int2bits(i) < 8, 0 ≤ i ⊦ fillsgn(8, int2bits(i)) = [], lastn(8, fillsgn(8, bitsand(int2bits(i), bits0 + bits))) = lastn(8, fillsgn(8, bitsand(bits, fillsgn(8, int2bits(i))))), bits0 + bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ bits ≠ [] ∧ bits0 ≠ [] → bitsand(bits, bits0) = bitsand(bits0, bits) subst: [bits0, bits] → [bits0 + bits, int2bits(i)] rotate: F spec: intops inst: name: and-com

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ []; Used terms: bits0 + bits, int2bits(i)