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Proof step 33 from proof byte-law-mult-one (previous step)

127 < j0 ∧ j0 < 256, j0 < 256, 0 ≤ i0, 0 ≤ j0 ⊦ i2b(j0 * j) = i2b((j0 - 256) * j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
0 < j0, 0 ≤ j0, 0 ≤ i0, j0 < 256, 127 < j0 ⊦ i2b(j0 * j) = i2b((j0 - 256) * j)

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)