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Proof step 2 from proof byte-law-neg (previous step)

⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i
Proof step 4:
¬(~128 ≤ i ∧ i ≤ 127) ⊦ i2b(~ i) = i2b(~ b2i(i2b(i)))

Rule argument

name: bib-in-01 rotate: F subst: [i] → [i]

Additional information

Used terms: i