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Proof step 22 from proof byte-law-neg (previous step)

i % 256 < ~127, i < i % 256, i < 0, i < ~128, ~128 ≤ i % 256 ⊦ i2b(~ i) = i2b(~(i % 256)), i % 256 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ i < j ↔ i +1 = j ∨ i +1 < j
Proof step 24:
(i % 256)+1 = ~127 ∨ (i % 256)+1 < ~127, i < i % 256, i < 0, i < ~128, ~128 ≤ i % 256 ⊦ i2b(~ i) = i2b(~(i % 256)), i % 256 = 0

Rule argument

seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [~127, i % 256] rotate: F spec: int-basic1 inst: name: lsrec

Additional information

Used terms: ~127, i % 256