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Proof step 25 from proof byte-law-neg (previous step)

~128 = i % 256, i < ~128, i < 0 ⊦ i2b(~ i) = i2b(128)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 26:
⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j))
Proof step 27:
~128 = i % 256, i < ~128, i < 0 ⊦ b2i(i2b(~ i)) = b2i(i2b(128))

Rule argument

name: i2b-equal rotate: F subst: [j, i] → [128, ~ i]

Additional information

Used terms: 128, ~ i